Physics Problem , Need Help Quickly.

StudentStudent Member
edited June 2014 in Advanced Level
Me prashneth hadana hati kiyala denna Puluwanda ??

1 ) Lamayek widuru bolayak 3.2m usaka sita bimata bamai. Eya bima wadi polapanina prawegaya , bima wadina prawegayen 3/4 k nam , widuru bolaya nagina usa kiyada ??
Bolaya palamuwara bima gatuna mohethe sita dewanawara bima gatena mohatha dakwa gatha wana kalaya kiyada ??
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Comments

  • yasasyasas Member
    Accepted Answer
    g=10ms-2
    පහලට
    v2=u2 + 2as
    v2=0 + 2*10*3.2
    v2=64
    v=8ms-1 බිම වදින ප්‍ර.
    පොලා පනින ප්‍ර = 8*3/4 =6ms-1 ඉහලට

    ඉහලට
    v2=u2 + 2as
    0=62 -2*10*s
    s=36/20
    s=1.8m බෝලය නගින උස

    ~O)
    ඉහලට

    s=ut+(1/2)at2
    0=6t - (1/2)10t2
    0=6 - 5t   {t අසමානයි 0}
    t=6/5 s
    t=1.2s

    ~O) ~O)
  • @Yasas - Thank U Very Much !! :)
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