me gana hadala denna.
Sin A  Sin(BC) = 2 CosB SinC
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A+B+C=pi lesa ganna wenawa. A,B,C thrikonayaka koona wenna one.
L.H.S= 2.cos{[A+BC]/2}.sin{[A(BC)]} = 2.cos{[(piC)C]/2}.sin{[(piB)B]/2} = 2.cos(pi/2 C).sin(pi/2 B) = 2.sinC.cosB = R.H.S
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